To work on these problems, open the Parsons editor:
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python3 parsons
Q1: Remove Odd Indices
Complete the function remove_odd_indices, which takes in a list lst and a boolean odd, and returns a new list with elements removed at certain indices. If odd is True, then the function should remove elements at odd indices; otherwise if odd is False, then the function should remove even indexed items.
Note that lists are zero-indexed; thus, the first element is at index 0, the second element is at index 1, etc.
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defremove_odd_indices(lst, odd): """ Remove elements of lst that have odd indices. >>> s = [1, 2, 3, 4] >>> t = remove_odd_indices(s, True) >>> s [1, 2, 3, 4] >>> t [1, 3] >>> l = [5, 6, 7, 8] >>> m = remove_odd_indices(l, False) >>> m [6, 8] """ "*** YOUR CODE HERE ***" if odd: return [lst[x] for x inrange(len(lst)) if x % 2 == 0] else: return [lst[x] for x inrange(len(lst)) if x % 2 == 1]
Q2: Smart Fridge
The SmartFridge class is used by smart refrigerators to track which items are in the fridge and let owners know when an item has run out.
The class internally uses a dictionary to store items, where each key is the item name and the value is the current quantity. The add_item method should add the given quantity of the given item and report the current quantity. You can assume that the use_item method will only be called on items that are already in the fridge, and it should use up the given quantity of the given item. If the quantity would fall to or below zero, it should only use up to the remaining quantity, and remind the owner to buy more of that item.
Finish implementing the SmartFridge class definition so that its add_item and use_item methods work as expected.
classSmartFridge: """" >>> fridgey = SmartFridge() >>> fridgey.add_item('Mayo', 1) 'I now have 1 Mayo' >>> fridgey.add_item('Mayo', 2) 'I now have 3 Mayo' >>> fridgey.use_item('Mayo', 2.5) 'I have 0.5 Mayo left' >>> fridgey.use_item('Mayo', 0.5) 'Uh oh, buy more Mayo!' """ def__init__(self): self.items = {} defadd_item(self, item, quantity): "*** YOUR CODE HERE ***" if item in self.items: self.items[item] += quantity else: self.items[item] = quantity returnf'I now have {self.items[item]}{item}' defuse_item(self, item, quantity): "*** YOUR CODE HERE ***" self.items[item] -= min(quantity, self.items[item]) if self.items[item] == 0: returnf'Uh oh, buy more {item}!' returnf'I have {self.items[item]}{item} left'
Code Writing Questions
Q3: Merge
Write a function merge that takes 2 sorted lists lst1 and lst2, and returns a new list that contains all the elements in the two lists in sorted order. Note: Try to solve this question using recursion instead of iteration.
defmerge(lst1, lst2): """Merges two sorted lists. >>> merge([1, 3, 5], [2, 4, 6]) [1, 2, 3, 4, 5, 6] >>> merge([], [2, 4, 6]) [2, 4, 6] >>> merge([1, 2, 3], []) [1, 2, 3] >>> merge([5, 7], [2, 4, 6]) [2, 4, 5, 6, 7] """ "*** YOUR CODE HERE ***" defhelper(lst1, n, lst2, m): if n == 0: return lst2 if m == 0: return lst1 res = [] if lst1[0] < lst2[0]: res.append(lst1[0]) res.extend(helper(lst1[1:], n - 1, lst2, m)) else: res.append(lst2[0]) res.extend(helper(lst2[1:], m - 1, lst1, n)) return res return helper(lst1, len(lst1), lst2, len(lst2))
"""Iteration res = [] i, j = 0, 0 while i < len(lst1) and j < len(lst2): if lst1[i] < lst2[j]: res.append(lst1[i]) i += 1 else: res.append(lst2[j]) j += 1 while i < len(lst1): res.append(lst1[i]) i += 1 while j < len(lst2): res.append(lst2[j]) j += 1 return res """
Use Ok to test your code:
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python3 ok -q merge✂️
Q4: Mint
A mint is a place where coins are made. In this question, you’ll implement a Mint class that can output a Coin with the correct year and worth.
Each Mint instance has a year stamp. The update method sets the year stamp to the present_year class attribute of the Mint class.
The create method takes a subclass of Coin and returns an instance of that class stamped with the mint’s year (which may be different from Mint.present_year if it has not been updated.)
A Coin’s worth method returns the cents value of the coin plus one extra cent for each year of age beyond 50. A coin’s age can be determined by subtracting the coin’s year from the present_year class attribute of the Mint class.
classMint: """A mint creates coins by stamping on years. The update method sets the mint's stamp to Mint.present_year. >>> mint = Mint() >>> mint.year 2021 >>> dime = mint.create(Dime) >>> dime.year 2021 >>> Mint.present_year = 2101 # Time passes >>> nickel = mint.create(Nickel) >>> nickel.year # The mint has not updated its stamp yet 2021 >>> nickel.worth() # 5 cents + (80 - 50 years) 35 >>> mint.update() # The mint's year is updated to 2101 >>> Mint.present_year = 2176 # More time passes >>> mint.create(Dime).worth() # 10 cents + (75 - 50 years) 35 >>> Mint().create(Dime).worth() # A new mint has the current year 10 >>> dime.worth() # 10 cents + (155 - 50 years) 115 >>> Dime.cents = 20 # Upgrade all dimes! >>> dime.worth() # 20 cents + (155 - 50 years) 125 """ present_year = 2021
def__init__(self): self.update()
defcreate(self, coin): "*** YOUR CODE HERE ***" return coin(self.year)
defupdate(self): "*** YOUR CODE HERE ***" self.year = Mint.present_year
classCoin: cents = None# will be provided by subclasses, but not by Coin itself
def__init__(self, year): self.year = year
defworth(self): "*** YOUR CODE HERE ***" return self.cents + max(0, Mint.present_year - self.year - 50)
classNickel(Coin): cents = 5
classDime(Coin): cents = 10
Use Ok to test your code:
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python3 ok -q Mint✂️
Q5: Vending Machine
In this question you’ll create a vending machine that only outputs a single product and provides change when needed.
Create a class called VendingMachine that represents a vending machine for some product. A VendingMachine object returns strings describing its interactions. Remember to match exactly the strings in the doctests – including punctuation and spacing!
Fill in the VendingMachine class, adding attributes and methods as appropriate, such that its behavior matches the following doctests:
classVendingMachine: """A vending machine that vends some product for some price. >>> v = VendingMachine('candy', 10) >>> v.vend() 'Nothing left to vend. Please restock.' >>> v.add_funds(15) 'Nothing left to vend. Please restock. Here is your $15.' >>> v.restock(2) 'Current candy stock: 2' >>> v.vend() 'You must add $10 more funds.' >>> v.add_funds(7) 'Current balance: $7' >>> v.vend() 'You must add $3 more funds.' >>> v.add_funds(5) 'Current balance: $12' >>> v.vend() 'Here is your candy and $2 change.' >>> v.add_funds(10) 'Current balance: $10' >>> v.vend() 'Here is your candy.' >>> v.add_funds(15) 'Nothing left to vend. Please restock. Here is your $15.' >>> w = VendingMachine('soda', 2) >>> w.restock(3) 'Current soda stock: 3' >>> w.restock(3) 'Current soda stock: 6' >>> w.add_funds(2) 'Current balance: $2' >>> w.vend() 'Here is your soda.' """ "*** YOUR CODE HERE ***" def__init__(self, name, price): self.name = name self.price = price self.num = 0 self.balance = 0 defrestock(self, num): self.num += num returnf"Current {self.name} stock: {self.num}" defadd_funds(self, amount): if self.num > 0: self.balance += amount returnf"Current balance: ${self.balance}" else: returnf'Nothing left to vend. Please restock. Here is your ${amount}.' defvend(self): if self.num == 0: returnf'Nothing left to vend. Please restock.' if self.balance < self.price: returnf"You must add ${self.price - self.balance} more funds." else: self.balance = self.balance - self.price self.num -= 1 if self.balance > 0: ret = f"Here is your {self.name} and ${self.balance} change." self.balance = 0 return ret elif self.balance == 0: returnf"Here is your {self.name}."
You may find Python’s formatted string literals, or f-strings useful. A quick example: